You are given the coefficients of a quadratic equation in order A, B & C.

You are given the coefficients of a quadratic equation in order A, B & C.

Where A is the coefficient of X²,  B is the coefficient of X and C is the constant term in the most simplified form.

Example: For  X² + 5X + 6 = 0, you are given the input as: 1 5 6.

Write a program to find all of the roots of the quadratic.

Note: The output should be up to 2nd decimal place (round off if needed) and in case of a recurring decimal use braces i.e. for eg: 0.33333..... => 0.33.

Note: Use Shri Dharacharya's Method to solve i.e. X = {-b + √(b² - 4ac) } / 2a & {-b-√(b² -4ac)} / 2a

Input Description:
Three numbers corresponding to the coefficients of x(squared), x and constant are given as an input in that particular order

Output Description:
Print the two values of X after rounding off to 2 decimal places if required.

Sample Input :
1 5 6

Sample Output :
-2.00
-3.00


 const readline = require('readline');
 const inp = readline.createInterface({
  input: process.stdin
 });
 const userInput = [];
 inp.on("line", (data) => {
 userInput.push(data);
 });
 inp.on("close", () => {
 var data = userInput[0].split(" ");
 var a = parseInt(data[0]);
 var b= parseInt(data[1]);
 var c=parseInt(data[2]);
var d=Math.sqrt((b*b)-(4*a*c))
var e=(-b+d)/(2*a)
var f=(-b-d)/(2*a)
var g=e.toFixed(2)
var h=f.toFixed(2)
console.log(g);
console.log(h)

 });